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The half life of radioactive Radon is `3.8 days` . The time at the end of which `(1)/(20) th` of the radon sample will remain undecayed is `(given log e = 0.4343 ) `A. `3.8` daysB. `1.65` dayC. `33` dayD. `76` day |
Answer» Correct Answer - B `M = M_(0)e^(-lambdat) rArr (M_(0))/(20) = M_(0)e^(-lambdat) rArr ln (1/20) = -lambdat` `rArr ((ln(20))/(ln2)) T_(1//2) = t rArr ((ln(2) + ln(10))/(ln2))T_(1//2) = t` `rArr t = 16.42` days |
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