1.

The half life period of a reaction is halved when the initial concentration is doubled. Calculate the order of reaction.

Answer»


SOLUTION :`t_(1//2) propto 1/([A_(0)]^(n-1)`
`(t_(1//2))_(1)/(t_(1//2))_(2)= ([A_(0)]_(2)^(n-1))/([A_(0)]_(1)^(n-1))`
`(t)/(t_(1//2)) = ((2A)/(a))^(n-1)`
`(2)^(1) = (2)^(n-1)`
`n-1=1` or n=2


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