1.

The half-lifefor decay of ""^(14)C by beta-emission is 5730 years.The fraction of ""^(14)C decays, in a sample that is 22,920 years old, would be

Answer»

`1//8`
`1//16`
`7//8`
`15//16`

Solution :`N/(N_0) = (1/2)^(n)`
Where, `N_0` = Initial amount, N = Amount left
`n = t/(t_(1//2))`
Given , `t_(1//2) = (22,920)/(5730) = 4 , N/(N_0) = (1/2)^(4) = 1/16 implies N = (N_0)/(16)`
The FRACTION of `""^(14)C` that DECAYED = `N_0 - N`
`=N_0 - (N_0)/(16) = 15/16 N_0`


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