1.

The half - lifeof a radioactive isotope is three hours. If the initial mass of the isotope was 300 g. the masswhichremainsundecayed in 18 hourswould be

Answer»

2.34 g
1.17 g
9.36 g
4.68 g

SOLUTION :NUMBER of half -lives(N) =` ("Total time")/( t_(1//2)) = 18/3 = 6`
` N = N_(0)/(2^(n)) = 300/2^(6)4.68 g`


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