1.

The half lifr of a particle of mass 1.6 xx 10^(-26) kg is 6.9 s and a stream of such particles is travelling with the kinetic energy of a particles is travelling with the kinetic energy of a particle being 0.05 eV. The fraction of particles which will decay when they travel a distance of 1 m is

Answer»

`0.1`
`0.01`
`0.001`
`0.0001`

Solution :`(dN)/(DT)=n LAMDA RARR(dN)/(dt)=lamda dt`
`(6.63)/(6.9)xx10^(-4) =10^(4)`


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