InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The hardness of water due to `HCO_3` is `122 p p m`. Select the correct statement(s).A. The hardness of water in terms of `CaCO_(3)` is 200 ppm.B. The hardness of water in terms of `CaCO_(3)` is 100 ppm.C. The hardness of water in terms of `CaCl_(2)` is 222 ppm.D. The hardness of water in terms of `MgCl_(2)` is 95 ppm. |
|
Answer» Correct Answer - B::D Since 2 " mol of "`HCO_(3)^(ɵ)` is present. So there should be one mole each of `CaCO_(3)`, `CaCl_(2)` and `MgCl_(2)` to have equal hardness. `thereforeMw of HCO_(3)^(ɵ)=61`, `ppm of HCO_(3)^(ɵ)=61xx2=122 g` in `10^(6) mL H_(2)O` `[Mw of CaCO_(3)=100,Mw of CaCl_(2)=111,Mw of MgCl_(2)=95g mol^(-1)]` `1 " mol of "CaCO_(3)-=100ppm` `1 " mol of "CaCl_(2)=111 ppm` `1 " mol of "MgCl_(2)=95 ppm` Hence, answer is (b) and (d). |
|