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The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other |
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Answer» Let the two numbers be a and b. Let the value of a be 161. Given: HCF = 23 and LCM = 1449 We know, a × b = HCF × LCM ⇒ 161 × b = 23 × 1449 ⇒ ∴ b = 23 ×1449/ 161 = 33327/161 = 207 Hence, the other number b is 207. |
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