1.

The HCF of two numbers is 27 and their LCM is 162. If one of the numbers is 54, what is the other number? (a) 36 (b) 45 (c) 9 (d) 81

Answer»

(d) 81 

Let the two numbers be x and y. 

It is given that: 

x = 54 

HCF = 27 

LCM = 162 

We know, 

x × y = HCF × LCM 

⇒ 54 × y = 27 × 162 

⇒ 54 y = 4374

⇒ ∴ y = \(\frac{4374}{54}\) = 81

LCM * HCF = Number 1 * Number 2

27 * 162 = 54 * x

x = 81.


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