the HCF of two numbers is 42 and their LEM is 2646. If one the number

1.	the HCF of two numbers is 42 and their LEM is 2646. If one the number is 441 find the other number .
Answer» GIVEN: The HCF of two numbers = 42 and The LCM of two numbers = 2646 One the NUMBER = 441 Let x be the other number. We have to find, the value of other number. Solution: We know that: LCM × HCF = First number × SECOND number ∴ 441 × x = 2646 × 42 Dividing both sides by 441, we get ⇒ 1 × x = 6 × 42 ⇒ x = 252 Thus, the other number is equal to "252".

the HCF of two numbers is 42 and their LEM is 2646. If one the number is 441 find the other number .

Answer»

The HCF of two numbers = 42 and

The LCM of two numbers = 2646

One the NUMBER = 441

Let x be the other number.

We have to find, the value of other number.

Solution:

We know that:

LCM × HCF = First number × SECOND number

∴ 441 × x = 2646 × 42

Dividing both sides by 441, we get

⇒ 1 × x = 6 × 42

⇒ x = 252

Thus, the other number is equal to "252".