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The heat change for the following reaction at `298 K` and constant pressure is `+7.3 kcal` `A_(@)B(s)to2A(s)+(1)/(2)B_(2)(g)` ,` DeltaH=+7.3 kcal` The heat change at constant volume would beA. `+7.3kcal`B. More than `7.3kcal`C. Less than `7.3 kcal`D. Zero |
Answer» Correct Answer - C `DeltaH=DeltaE+Deltan_(g)RT` or `DeltaE=DeltaH-Deltan_(g)RT` `:. DeltaE=+7.3-(1)/(2)xx2xx298` `=7300 cal-298` `=7002 cal=7.00 kcal` |
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