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The heat of atomisation of `PH_(3)(g)` and `P_(2)H_(4)(g)` are `954 kJ mol^(-1)` and `1485 kJ mol^(-1)` respectively. The `P-P` bond energy in `kJ mol^(-1)` is |
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Answer» Correct Answer - 213 kJ/mol `PH_(3) rarr P+3H" "DeltaH=954` `P-H` bond enthalpy `=954/3=318 kJ` `H-underset(H)underset(|)(P)-underset(H)underset(|)(P)-H rarr 2P+4H" "DeltaH=1485` `1485=P-P+(4xx318)` `P-P=213" kJ mol"^(-1)` |
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