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The heat of atomisation of `PH_(3(g))` is `228kcal mol^(-1)` and that of `P_(2)H_(4)` is `355kcal mol^(-1)`. Calculate the average bond energy of `P-P` bond.A. 102B. 51C. 26D. 204 |
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Answer» Correct Answer - B `PH_(3) rarr P+3H,DeltaH=228` `H_(2)P-PH_(2) rarr 2P+4H,DeltaH=355` `e_(P-P)+4xxe_(P-H)=355` `e_(P-P)+4xx(228)/(3)=355` `:. e_(P-P)=51` |
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