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The heat of combustion of ethanol determinal in a bomb calorimeter is -670.48 K. Cals `"mole"^(-1)` at `25^(@)C`. What is `Delta H` at `25^(@)C` for the reaction :-A. `-335.24` K. Cals.B. `-671.08` K. Cals.C. `-670.48` K. Cals.D. `+670.48` K. Cals. |
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Answer» Correct Answer - B `C_(2)H_(5)OH_((l))+3O_(2(g))rarr 2CO_(2(g))+3H_(2)O_((l))` In Bomb calorimeter `Delta E = 670.48 kCal mol^(-1)` `Delta H=Delta E + Delta n_(g)RT` `Delta H=-670.48-1xx2xx10^(-3)xx298` |
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