InterviewSolution
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InterviewSolution
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The heat of combustion of `H_(2)(g)` at constant pressure and `300k` is `-280kJ mol^(-1)`. What will be the heat of combustion at constant volume and at `300K`? |
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Answer» `H_(2)(g) = (1)/(2)O_(2)(g) rarr H_(2)O(l) DeltaH =- 280 kJ mol^(-1)` `DeltaH = DeltaU +DeltanRT, Deltan = 0 - (3)/(2) =- (3)/(2)`, `DeltaH = DeltaU -(3)/(2) xx 8.314 xx 300` `- 280 kJ = DeltaU - (74826)/(20) xx (1)/(1000) kJ` `rArr DeltaU =- 276.2587 kJ` |
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