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The heat of formation of the compound in the following reaction is `H_(2)(g)+Cl_(2)(g)to2HCl(g)+44kcal`A. `-44 kcal mol^(-1)`B. `-22 kcal mol^(-1)`C. `11 kcal mol^(-1)`D. `-88 kcal mol^(-1)` |
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Answer» Correct Answer - B `DeltaH_(f)` refer to formation of `1` mole of `HCl(g)` in this case. |
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