1.

The heat of formation of water is 260 kJ. How much H_(2)O is decomposed by 130 kJ of heat?

Answer»

0.25 mol
1 mol
0.5 mol
2 mol

Solution :The REACTION for the formation of water is as
`H_(2)+(1)/(2)O_(2) to H_(2)O,DeltaH=260kJ`. . (i)
On reversing Eq. (i), we get
`underset(1mol)(H_(2)O) to H_(2)+(1)/(2)O_(2),DeltaH=-260kJ`. . (ii)
`because` By 260 kJ heat, water decomposed=1 mol
`therefore `130 kJ heat will decompose water`=(1xx130)/(260)=0.5`mol


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