The height y and horizontal distance x covered by a projectile in a time 1 seconds are given by the equations y = 8t - 5t^(2) and x = 6t. If x and y are measured in metres, the velocity of projection is

The height y and horizontal distance x covered by a projectile in a ti

1.	The height y and horizontal distance x covered by a projectile in a time 1 seconds are given by the equations y = 8t - 5t^(2) and x = 6t. If x and y are measured in metres, the velocity of projection is
Answer» `8 MS^(-1)` `6 ms^(-1)` `14 ms^(-1)` `10 ms^(-1)` Answer :D

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The height y and horizontal distance x covered by a projectile in a time 1 seconds are given by the equations y = 8t - 5t^(2) and x = 6t. If x and y are measured in metres, the velocity of projection is

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