1.

The high reactivity of alkyl halides can be explained in terms of nature of C-X bond which is a highly polarised covalent bond. This polarity is responsible for the nucleophilic substitution reaction of alkyl halides which jmostly occur by S_(N^(1)) and S_(N^(2)) mechanisms. S_(N^(1)) reaction is a two step process and in the first step R-X ionises to give carbocation (slow process). IN the second step, the nucleophile attacks the carbocation from either side to form the product (fast process). IN S_(N^(1)) reaction, there can be racemization and inversion. S_(N^(1)) reaction is favoured by heavy (bulky) group on the carbon atom attached to halogens. IN S_(N^(2)) reaction, the strong nucleophile OH^(-) attacks fromt he opposite side Of the halogen atom to give an intermediate (transition state), which breaks to yields to product (alcohol) and leaving group (X^(-)). The alcohol has a configuratio opposite to that of the halide and is said to proceed with inversion of configuration. S_(N^(2)) reaction is favoured by small groups on the carbon atom attached to halogen. Q. The main product formed in the following reaction is : CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)Br+CH_(3)CH_(2)O^(-)overset(S_(N^(1))to

Answer»

`CH_(3)-UNDERSET(CH_(3))underset(|)(C)H-CH_(2)OCH_(2)CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-OCH_(2)CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(3)OH`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-OH`

Solution :It is expected to be the major product because the nucleophile `(C_(2)H_(5)O^(-))` will prefer to COMBINE with `CH_(3)underset(CH_(3))underset(|)(C)Hoversete(o+)(CH_(2))` carbocation (primary) due to minimum steric hindrance involved.


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