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The highest oxidation state is exhibited by the transition metals with configuration:A. `(n - 1) d^(3) ns^(2)`B. `(n - 1) d^(5) ns^(1)`C. `(n - 1) d^(5) ns^(2)`D. `(n - 1) d^(8) ns^(2)` |
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Answer» Correct Answer - C it show maximum oxidation state equal to `+ 7` because the energy of `(n - 1)` d and ns orbitals are nearly same and thus seven electrons can participate in bonding. |
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