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| 1. |
The horizontal and vertical components of earth’s magnetic field at a place are 0.22G and 0.38G respectively. Calculate the angle of dip and resultant intensity of earth’s field. |
| Answer» Solution :`tan delta = (B_(V))/(B_(H)) = (0.38 )/(0.22) = 1.73 = 60^@ , B = SQRT(B_(H)^(2)+ B_(V)^(2))= 0.44` G | |