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The horizontal component and vertical components of Earth's maganetic field at a plase are 0.15 G and 0.26 G respectively. Calculate the angle of dip and resultant magnetic field. |
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Answer» Solution :`B_(H)` = 0.15 G and `B_(v)` = 0.26 G TAN 1 = `(0.26)/(0.15) RARR " I " = tan^(-1) (1.732) = 60^(@)` The resultant magnetic field of the earth is B = `sqrt(B_(H)^(2) + B_(H)^(2)) = 0.3G` |
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