1.

The horizontal component of earth's magnetic field is 3 xx 10^(-4) T. The magnetic dip angle is 45°. Find the vertical component.

Answer»

`sqrt(3) xx 10^(-4)` T
`3 xx 10^(-4)` T
`(1)/(sqrt(3)) xx 10^(-4) `T
`10^(-5)` T

Solution :For dip ANGLE
`tan phi = (B_v)/( B_h) ""[phi = 45^(@) , B_(h) = 3 xx 10^(-4) ]`
`therefore B_(V) = tan phixx B_(h) `
`= tan 45^(@) xx 3 xx10^(-4)`
`= 1 xx 3 xx 10^(-4) ""[tan 45^(@) =1]`
`= 3 xx 10^(-4)` T


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