1.

The horizontal component of flux density of earth’s magnetic field is 1.7 × 10^(-5) tesla. The value of horizontal component of intensity of earth’s magnetic field will be ?

Answer»

24.5 A/m
13.5 A/m
0.135 a/m
1.35 A/m

Solution :`H=(B)/(mu_(0))=(1.7xx10^(-5)Wb//m^(2))/(4pxx10^(-7)Wb//A-m)=13.5A//m`


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