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The hybridisation of phosphorus in `POCl_3` is the same asA. P in `PCl_3`B. S in `SF_4`C. Cl in `ClF_3`D. B in `BCl_3` |
Answer» Correct Answer - A P in `POCl_3` is `sp^3` hybridised i.e., H=`1/2[5+3]=4` P in `PCl_3` is also `sp^3` hybridised i.e., H=`1/2[5+3]=4` |
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