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The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively areA. `sp,sp^(3)` and `sp^(2)` respectivelyB. `sp,sp^(2)` and `sp^(3)` respectivelyC. `sp^(2),sp` and `sp^(3)` respectivelyD. `sp^(2),sp^(3)` and `sp ` respectively |
Answer» Correct Answer - B For `NO_(2)^(+) : H=1/2(5+0+0-2) =2 :. Sp` hybridization For `NO_(3)^(-) : H=1/2[5+0+1-0] ==3 :. Sp^(2)`-hybridization For `NH_(4)^(+) : H=1/2 [5+4+0-1]=4 , :. Sp^(3)` hybridisation |
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