1.

The hydrogen atom in the ground state excited by means of light of lambda= 975 Å. How many different hires are possible in resultant spectrum?

Answer»

4
3
2
6

Solution :`E_(n)=Z^(2). E_(0)/n^(2)`
For n=1 to `n=oo`, transition is ionisation ENERGY of hydrogen,
`13.6 =E_(0) (1/1^(2)-1/oo^(2)) or E_(0)=13.6eV`
`E_(n)=-(13.6)/(n^(2))eV`
`E_(n)=-(13.6)/(n^(2)eV`
`E=hv=(hc)/(lambda)=2.04 XX 10^(-18)J`
Let the ELECTRON jump from n=1 n=m after absorbing photon
`triangleE=E_(m)-E_(1)=13.6 (1/1^(2)-1/m^(2))eV`
then m=4
so there ar 6 possible lines EVOLVED.


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