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The hydrogen bonds are encountered in `HF, H_2 O, NH_3` and `HF_2^-`. The relative order of energies of hydrogen bonds isA. `HF gt H_(2)O gt H_(3)N gt HF_(2)^(-)`B. `H_(2)O gt HF_(2)^(-) gt HF gt NH_(3)`C. `HF gt HF_(2)^(-) gt H_(2)O gt NH_(3)`D. `HF_(2)^(-) gt HF gt H_(2)O gt NH_(3)` |
Answer» Correct Answer - D Higher is the electronegativity, stronger is the H-bond. Fluorine has more electronegativity among the given compound. In `HF_(2)^(-)` there are two fluorine atoms that results into even stronger H-bonding. |
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