InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The hydrolysis constant for `ZnCl_(2)` will be where `K_(b)` is effective dissociation constant of base `Zn^(++)`A. `K_(h)=(K_(w))/(K_(b))`B. `K_(h)=(K_(w)^(2))/(K_(b))`C. `K_(h)=(K_(w)^(2))/(K_(b)^(2))`D. `K_(h)=(K_(b))/(K_(w)^(2))` |
|
Answer» Correct Answer - B `Zn^(++)+2H_(2)OhArrZn(OH)_(2)+2H^(+)` `:. K_(h)=([Zn(OH)_(2)][H^(+)]^(2))/([Zn^(++)])` (`1`) `Zn(OH)_(2)hArrZn^(++)+2OH^(-)` `:. K_(b)=([Zn^(++)][OH^(-)]^(2))/([Zn(OH)_(2)])`, `K_(w)=[H^(+)][OH^(-)]` `:. (K_(w)^(2))/(K_(b))=K_(b)` |
|