1.

the hypotenuse of a right angled triangle is 4 times as long as the perpendicular drawn to it from the opposite vertex.then find the smallest angle of the triangle​

Answer»

ANSWER:

ANSWER

In △ABC LET ∠ACB=θ, BD=x⇒AC=4x

And cosθ=

AC

BC

=

4x

BC

.......(1)

In △BCD,sinθ=

BC

BD

=

BC

x

.....(2) From (1) and (2), we get,

sinθcosθ=

4

1

⇒sin2θ=30

∘

⇒θ=15

∘

Therefore, ∠BAC=90

∘

−15

∘

=75

∘

SOLUTION


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