1.

The hypotenuse of an isosceles right triangle is what is its area?

Answer» LET the base be a

PERPENDICULAR = a

Hypotenuse = sqrt ( a^2 + a^2)

=> sqrt ( 32) = sqrt ( a^2 + a^2)

=> 32 = 2a^2

=> a^2 = 16

=> a = 4

Base = 4 cm

Perpendicular = 4 cm

Area = Base × Perpendicular / 2

= 4 × 4 / 2

= 8 cm^2


Discussion

No Comment Found