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The image of point `P` when viewed from top of the slabs will be A. `2.0cm` above `P`B. `1.5cm` above `P`C. `2.0 cm` below `P`D. `1 cm` above `P` |
Answer» Correct Answer - D The two slabs will shift the image a distance `d=2(1+(1)/(mu))t=2(1-(1)/(1.5))(1.5)=1.0 cm` Therefore, final image will be `1 cm` above point `P`. |
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