The image of the line x−13=y−31=z−4−5 in the plane 2x−y+z+3=0 is the line a) x+33=y−51=z−2−5 b) x+3−3=y−5−1=z+25 c) x−33+y+51=z−2−5 d) x−3−3=y+5−1=z−25

The image of the line x−13=y−31=z−4−5 in the plane 2x−y+z+3=

1.	The image of the line x−13=y−31=z−4−5 in the plane 2x−y+z+3=0 is the line a) x+33=y−51=z−2−5 b) x+3−3=y−5−1=z+25 c) x−33+y+51=z−2−5 d) x−3−3=y+5−1=z−25
Answer» The image of the line $\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}$ in the plane $2 x - y + z + 3 = 0$ is the line a) $\frac{x + 3}{3} = \frac{y - 5}{1} = \frac{z - 2}{- 5}$ b) $\frac{x + 3}{- 3} = \frac{y - 5}{- 1} = \frac{z + 2}{5}$ c) $\frac{x - 3}{3} + \frac{y + 5}{1} = \frac{z - 2}{- 5}$ d) $\frac{x - 3}{- 3} = \frac{y + 5}{- 1} = \frac{z - 2}{5}$

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The image of the line x−13=y−31=z−4−5 in the plane 2x−y+z+3=0 is the line a) x+33=y−51=z−2−5 b) x+3−3=y−5−1=z+25 c) x−33+y+51=z−2−5 d) x−3−3=y+5−1=z−25

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