InterviewSolution
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InterviewSolution
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The incenter of the triangle formed by the axes and the line `x/a+y/b=1` |
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Answer» `(x_1,y_1)=(a,0)` `(x_2,y_2)=(0,b)` `(x_3,y_3)=(0,0)` `l=sqrt(0^2+b^2)=|b|` `m=sqrt(a^2+0^2)=|a|` `n=sqrt(a^2+b^2)` `I=(a|b|+b|a|+o)/(|a|+|b|+sqrt(a^2+b^2)),(b|a|+0+0)/(|a|+|b|+sqrt(a^2=b^2)}` `I=(a|b|)/(|a|+|b|+sqrt(a^2+b^2)),(|a|b)/(|a|+|b||sqrt(a^2+b^2)}` When a>0,b>o,|a|=a,|b|=b. option c is correct. |
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