The incorrect formula for entropy for a calorically perfect gas is____(a) ds=0(b) s=s(p,T)(c) s2-s1=cvln\(\frac {T_2}{T_1}\)+Rln\(\frac {v_2}{v_1}\)(d) s2-s1=cpln\(\frac {T_2}{T_1}\)-ln\(\frac {p_2}{p_1}\)I got this question in semester exam.My enquiry is from A Brief Review of Thermodynamics topic in portion Compressible Flow – Preliminary Aspects of Aerodynamics

The incorrect formula for entropy for a calorically perfect gas is____

1.	The incorrect formula for entropy for a calorically perfect gas is____(a) ds=0(b) s=s(p,T)(c) s2-s1=cvln\(\frac {T_2}{T_1}\)+Rln\(\frac {v_2}{v_1}\)(d) s2-s1=cpln\(\frac {T_2}{T_1}\)-ln\(\frac {p_2}{p_1}\)I got this question in semester exam.My enquiry is from A Brief Review of Thermodynamics topic in portion Compressible Flow – Preliminary Aspects of Aerodynamics
Answer» Correct answer is (a) ds=0 Easy explanation: The change in entropy is zero only for an adiabatic PROCESS of a GAS. Calorically perfect gas has constant specific heats, which makes the integration between the INITIAL and final state easier. The final FORM of the equation comes out as s2-s1=cvln\(\FRAC {T_2}{T_1}\)+Rln\(\frac {v_2}{v_1}\) and s2-s1=cpln\(\frac {T_2}{T_1}\)-ln\(\frac {p_2}{p_1}\). As visible from these equations s=s(p, T).

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