1.

The incorrect statement for 14 g of CO is

Answer»

It OCCUPIES 2.24 litre at NTP
It corresponds to `1/2` mole of `CO`
It corresponds to same mole of `CO` and `N_(2)`
It corresponds to `3.01xx10^(23)` molecules of `CO`

Solution :14 G of `CO=14/28=0.5` mole
0.5 mole `=3.01xx10^(23)` molecules
The molecular WEIGHT of
`CO=(15+16)=28`
The molecular weight of
`N_(2)=14+14=28`
Therefore, the incorrect STATEMENT is that it occupies 2.24 litre at NTP.


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