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| 1. |
The increase in length of a wire on stretching is0.04 %. If it's poisson's ratio is 0.5, at what percentage the diameter will reduce ? |
| Answer» Solution :`(DELTA L) /L= (4)/(100 XX 100) = 4 xx 10^-4` there for `(delta D)/D = delta( delta L)/L =1/2 xx 4 xx 10^-4 = 2 xx 10^-4` `(delta D)/D = 0.02/100 = 0.02%` | |