The indicator diagram for two processes 1 and 2 carrying on an ideal gas is shown in Fig. If `m_(1)` and `m_(2)` be the slopes `(dP//dV)` for process 1 and process 2, respectively, then A. `m_(1) = m_(2)`B. `m_(1) gt m_(2)`C. `m_(1) lt m_(2)`D. `m_(2) C_(V) = m_(1) C_(P)`

The indicator diagram for two processes 1 and 2 carrying on an ideal g

1.	The indicator diagram for two processes 1 and 2 carrying on an ideal gas is shown in Fig. If `m_(1)` and `m_(2)` be the slopes `(dP//dV)` for process 1 and process 2, respectively, then A. `m_(1) = m_(2)`B. `m_(1) gt m_(2)`C. `m_(1) lt m_(2)`D. `m_(2) C_(V) = m_(1) C_(P)`
Answer» Correct Answer - C::D During expansion, an isotherm lies above an adiabat Also `(` Slope of an adiabat `)` ` gamma(` Slope of an isotherm `)` `implies m_(2)=(C_(p))/(C_(v))(m_(1))` `implies m _(2) C_(v)= m _(1) C _(p)` Since `gamma -1`, ` implies m _(2) gt m_(1)`

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The indicator diagram for two processes 1 and 2 carrying on an ideal gas is shown in Fig. If `m_(1)` and `m_(2)` be the slopes `(dP//dV)` for process 1 and process 2, respectively, then A. `m_(1) = m_(2)`B. `m_(1) gt m_(2)`C. `m_(1) lt m_(2)`D. `m_(2) C_(V) = m_(1) C_(P)`

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