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The initial concentration of N_2O_5 in the first order reaction N_2O_5 to 2NO_2 + 1//2O_2 was 1.24 xx10^(-2) "mol L"^(-1) at 318 K. The concentration of N_2O_5 after 60 minutes was 0.20 xx 10^(-2) "mol L"^(-1). Calculate the rate constant of the reaction at 318 K. |
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Answer» SOLUTION :`K=2.303/t "LOG"([A]_0)/([A])=2.303/t "log"[N_2O_5]_0/[N_2O_5]_t=2.303/60 "log" (1.24xx10^(-2))/(0.2xx10^(-2))` `=2.303/60"log"6.2 =2.303/60xx0.7924 "min"^(-1)` `=0.0304 "min"^(-1)` |
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