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The initial position and velocity of a body moving in SHM with period `T = 0.25s` are `x = 5.0cm` and `v = 218cm//s`. What are the amplitude and phase constant of the motion ? |
Answer» Correct Answer - A::C::D `omega = (2pi)/(T) = (2pi)/(0.25) = (8pi)rad//s` `x = A sin(omega t + phi)` `U = (dx)/(dt) = omega A cos (omega t + phi)` At `t = 0` `x = Asin phi` `:. 5 = A sin phi` ...(i) `U = omega A cos phi = (8pi) A cos phi` `:. 218 = (8pi A)cos phi` ...(ii) Solving Eqs. (i) and (ii) we get, `A = 10 cm` and `phi = (pi)/(6)` or `30^(@)` |
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