The initial rate , `-(d [A])/(dt)` at t = 0 was found to be `2 . 6 xx 10^(-2)` mol `L^(-1) s^(-1)` for the reaction `A + 2B to ` Products The initial rate , `- (d[B])/(dt)` at t = 0 isA. `0.01` mol `L^(-1) s^(-1)`B. `2.6 xx 10^(-2)` mol `L^(-1) s^(-1)`C. `5.2 xx 10^(-2)` mol `L^(-1) s^(-1)`D. `6.5 xx 10^(-3)` mol `L^(-1) s^(-1)`

The initial rate , `-(d [A])/(dt)` at t = 0 was found to be `2 . 6 xx

1.	The initial rate , `-(d [A])/(dt)` at t = 0 was found to be `2 . 6 xx 10^(-2)` mol `L^(-1) s^(-1)` for the reaction `A + 2B to ` Products The initial rate , `- (d[B])/(dt)` at t = 0 isA. `0.01` mol `L^(-1) s^(-1)`B. `2.6 xx 10^(-2)` mol `L^(-1) s^(-1)`C. `5.2 xx 10^(-2)` mol `L^(-1) s^(-1)`D. `6.5 xx 10^(-3)` mol `L^(-1) s^(-1)`
Answer» Correct Answer - c `A + 2 B implies ` products `-(d[A])/(dt) = (-d[B])/(2dt)` `2.6 xx 10^(-2)` mol `L^(-1) s^(-1) = (-d[B])/(2dt)` `(-d[B])/(dt) = 2 xx 2.6 xx 10^(-2)` `= 5.2 xx 10^(-2)` mol `L^(-1) s^(-1)`

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