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The input resistance of a silicon transistor is `100 Omega`. Base current is changed by `40 muA` which results in a change in collector current by `2 mA`. This transistor is used as a common-emitter amplifier with a load resistance of `4k Omega`. The voltage gain of the amplifier isA. 3000B. 4000C. 1000D. 2000 |
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Answer» Correct Answer - D `"Current gain "(beta)=(DeltaI_(C))/(DeltaI_(B))=(2xx10^(-3))/(40xx10^(-6))` `beta=50` `"Voltage gain "=beta((R_("out"))/(R_("in")))` `=50((4xx10^(3))/(100))` `=2000` |
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