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The integrated rate expression for a first order reaction can be written asA. (a-x)=a exp `(-k_(1)t)`B. x=a exp `(-k_(1)t)`C. (a-x)=t exp `(-k_(1)t)`D. (a-x)=a exp `(-k_(1)//t)` |
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Answer» Correct Answer - A Let the reaction be `{:(a" "0" ""initial concentration"),(A" "to" "B" "),((a-x)" "x" ""concentration at time"t):}` `In(a-x)/(a)=-K_(1)t)` or `(a-x)/(a)=e^(-K_(1)t)` In the above expression `(a-x)` will be zero only at infinite time. |
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