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The integrating factor of differential equation `cos x (dy)/(dx)+y sin x =1` isA. cos xB. tan xC. sec xD. sin x |
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Answer» Given, that `cosx (dy)/(dx)+y sin x=1` `Rightarrow (dy)/(dx)+y tan x=sec x` Here, P=tan x Q=sec x `IF=e^(intPdx)=e^(inttanxdx)=e^(log secx)` `therefore =sec x` |
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