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The integrating factor of differential equation `cos x (dy)/(dx)+y sin x =1` isA. cos xB. tan xC. sec xD. sin x

Answer» Given, that `cosx (dy)/(dx)+y sin x=1`
`Rightarrow (dy)/(dx)+y tan x=sec x`
Here, P=tan x Q=sec x
`IF=e^(intPdx)=e^(inttanxdx)=e^(log secx)`
`therefore =sec x`


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