InterviewSolution
Saved Bookmarks
| 1. |
The intensity of gamma-"rays" from a given source is I. On passing through 36mm of lead, it is reduced to I/8. The thickness that will reduce the intensity to I/2, it |
|
Answer» 18mm `I=I_(0)=e^(-mux)` `log_(e) 1/I_(0)=-mu x` ...........(i) `log_(e) (I.)/(I_(0))=-mu x. ..........(ii)` From eqn (i) `log_(e) (1/8) =-mux=-36 x..........(iii)` `log_(e) (1/2)=-mu x. .........(IV)` From eqn (iii) `3log_(e) (1/2) =-36X .........(v)` Divide (v) by (iv) `(3 log_(e) ""1/2)/(log_(e) ""1/2)=(-36mu)/(-mu x.)` `3=(12 xx 3)/(x.)` x.=12 mm |
|