1.

The intensity of magnetic field at a point X on the axis of a small magnet is equal to the field intensity at another point Y on its equatorial axis. The ratio of distances of X and Y from the centre of the magnet will be

Answer»

`(2)^(-3)`
`(2)^(-1//3)`
`2^3`
`2^(1//3)`

SOLUTION :If `d_1` is the distance of POINT X on AXIAL line and `d_2` is distance of point Y on equatorial line, then
`B_1=mu_0/(4pi) (2M)/d_1^3 , B_2=mu_0/(4pi) M/d_2^3`
As `B_1=B_2`
`therefore mu_0/(4pi) M/d_1^3 = mu_0/(4pi) M/d_2^3 RARR d_1^3 = 2d_2^3 rArr d_1/d_2=2^(1//3)`


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