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The intensity of magnetization of a bar magnet is 5.0 xx 10^(4) A m^(-1) The magnetic length and the area of cross-section of the magnet are 12 cm and 1 cm^(2) respectively. The magnitude of magnetic moment of this bar magnet is (in SI unit) |
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Answer» 0.6 `I = 5.0 XX 10^(4)Am^(-1)` Magneetic length, `L = 12 cm = 12 xx 10^(-2)m` Area of magnetisation, `I = "Magnetic moment (M)"/"Volume (V)"` or M = IV = IAL `=(5.0 xx 10^(4)A m^(-1)) (1xx 10^(-4) m^(2))(12 xx 10^(-2)m)` `= 60 xx 10^(-2)A m^(-2) = 0.6A m^(2)` |
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