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The intensity of the electric field required to keep a water drop of radius 10^-5 cm justsuspend in air when charged with one electron is approximately. |
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Answer» (A) 130V/cm mg =Ee `THEREFORE E = (mg)/e = (4/3pi^(2)rhog)/e` `=(4 xx 3.14 xx (10^(-7))^(3) xx 10^(3)xx 9.8)/(3 xx 1.6 xx 10^(-19))` `=25.643 xx 10^(1) = 256` = 260 N/C (UPTO two SIGNIFICANT numbers) |
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