1.

The intensity of the electric field required to keep a water drop of radius 10^-5 cm justsuspend in air when charged with one electron is approximately.

Answer»

(A) 130V/cm
(B) 26V/m
(C) 130 N/C
(D) 260 N/C

Solution :F=Ee
mg =Ee
`THEREFORE E = (mg)/e = (4/3pi^(2)rhog)/e`
`=(4 xx 3.14 xx (10^(-7))^(3) xx 10^(3)xx 9.8)/(3 xx 1.6 xx 10^(-19))`
`=25.643 xx 10^(1) = 256`
= 260 N/C (UPTO two SIGNIFICANT numbers)


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