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The internal energy change in a system that has absorbed `2 kcal` of heat and done `500J` of work isA. `8900J`B. `6400J`C. `5400J`D. `7900J`

Answer» Correct Answer - D
Heat given to a system `(DeltaQ)` is equal to the sun of increases in the internal energy `(Deltau)` and the work done `(DeltaW)` by the system against the surrounding and `1 cal=4.2J`.
According to first law of thermodynamics
`DeltaU=Q-W`
`=2xx4.2xx1000-500=7900J`.


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