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The internal energy change in a system that has absorbed `2 kcal` of heat and done `500J` of work isA. `8900J`B. `6400J`C. `5400J`D. `7900J` |
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Answer» Correct Answer - D Heat given to a system `(DeltaQ)` is equal to the sun of increases in the internal energy `(Deltau)` and the work done `(DeltaW)` by the system against the surrounding and `1 cal=4.2J`. According to first law of thermodynamics `DeltaU=Q-W` `=2xx4.2xx1000-500=7900J`. |
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