The internal energy of a gas is given by `U=1.5pV. It expandeds from `100 cm^(3) to 200 cm^(3)` against a constant pressure of `1.0xx10^(5)` Pa. calculate the heat absorbed by the gas in the process.

The internal energy of a gas is given by `U=1.5pV. It expandeds from `

1.	The internal energy of a gas is given by `U=1.5pV. It expandeds from `100 cm^(3) to 200 cm^(3)` against a constant pressure of `1.0xx10^(5)` Pa. calculate the heat absorbed by the gas in the process.
Answer» Correct Answer - B Delta U = 1.5pV` `DeltaV = (20-100)cm^3 = 100cm^3` ` = 10^(-4)m^3` `P = 1xx10^5pa` `Delta U = 1.5xx10^5xx10^(-4) = 15J` `Delta W = 10^5xx10^(-4) = 10J` `DeltaQ = Delta U+DeltaW = 10+15 = 25J`

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The internal energy of a gas is given by `U=1.5pV. It expandeds from `100 cm^(3) to 200 cm^(3)` against a constant pressure of `1.0xx10^(5)` Pa. calculate the heat absorbed by the gas in the process.

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