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The internal energy of a gas is given by `U= 5 + 2PV`. It expands from `V_(0)` to `2V_(0)` against a constant pressure `P_(0)`. The heat absorbed by the gas in the process is :-A. `-3P_(0)V_(0)`B. `3P_(0)V_(0)`C. `2P_(0)V_(0)`D. `P_(0)V_(0)` |
Answer» Correct Answer - B `DeltaU = 2P_(0) DeltaV` & `W = P_(0)DeltaV` So `Q = W + DeltaU = 3P_(0)DeltaV = 3P_(0)V_(0)` |
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